[fitswcs] Relativistic transverse Doppler effect [RESEND]
Mark Calabretta
Mark.Calabretta at atnf.CSIRO.AU
Sun Apr 18 20:34:05 EDT 2004
Greetings,
When Eric announced the latest draft of Paper III on Feb/24 he mentioned
that I would make a suggestion regarding the introduction of a new
keyword to record the orientation angle for resolving the transverse
relativistic velocity.
Figure 1 of the paper shows that the transverse velocity potentially
has a very significant effect.
To be concrete, I like to think of a relativistic jet emanating from a
distant galaxy. In principle, the galaxy's systemic, cosmological
redshift can be measured separately and used to correct the jet's
observed redshift thereby providing its kinematic redshift (i.e.
associated with a true velocity) in the reference frame of the galaxy.
Clearly knowledge of the velocity is fundamental in studying jet
kinematics and dynamics. However, it can only be computed from the
kinematic redshift if the jet's orientation angle is known. Note that
the equations involving velocity in Table 3 are actually only correct
if the transverse velocity is zero. For example, Eq. (12) is just a
special case of Eq. (2). This is why the velocity is always referred
to in the paper as being "apparent".
There are instances where the orientation angle may be inferred by
geometry (e.g. by the observed tilt of an accretion disk) or by
modelling. I therefore propose that the paper be augmented
1) by the introduction of a new keyword to record the orientation
angle, and
2) by modifying the eight equations involving velocity in Table 3
to take account of this orientation angle.
For example, Eq. (12) would become
1 + v sin(theta)/c
lambda = lambda0 ------------------
sqrt(1 - v^2/c^2)
and its inverse, Eq. (16),
L*lambda^2 - lambda0^2 sin(theta)
v = c ----------------------------------- ,
lambda^2 + lambda0^2 sin^2(theta)
where
L = +/- sqrt{1 - (lambda0/lambda)^2 cos^2(theta)} .
theta is defined so that
theta = -90 is towards the observer,
theta = 0 is transverse, and
theta = +90 is away from the observer,
and thus
v_r = v sin(theta) ...radial velocity component
v_t = v cos(theta) ...transverse velocity component
v = sqrt(v_r^2 + v_t^2)
Equations (8,9,12-17) would need to be changed, and unfortunately the
derivatives would probably be rather messy.
Mark Calabretta
ATNF
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